Moon Rabbits
02-14-2008, 10:28 PM
How would I solve:
2 = 6(3 ^ 4f - 2)
27(3 ^ 3x + 1) = 3
I've tried a million different methods, but I can't figure out how to get rid of the 6(~) and 27(~) on the outside of the equations without leaving 2/6 or 3/27 on the other side of the equation, which I can't turn into a negative exponent because the numerators are not one.
I googled for a solution but only came up with answers involving "logs" which I haven't learned to apply yet.
2 = 6(3 ^ 4f - 2)
27(3 ^ 3x + 1) = 3
I've tried a million different methods, but I can't figure out how to get rid of the 6(~) and 27(~) on the outside of the equations without leaving 2/6 or 3/27 on the other side of the equation, which I can't turn into a negative exponent because the numerators are not one.
I googled for a solution but only came up with answers involving "logs" which I haven't learned to apply yet.