Math problem

[Dignified Pauper]

1, 3, 4, 6 must equal 24, but can be only used once
add, subtract, etc

occam's razor doesnt apply
you dont need them all, but they all must be used
its a mind twister

+ - x / ( ) is all that is used.

My professor gave us this problem, and we're furiosly trying to figure it out. Any help would be appreciated.

[TasteyPies]

1x + 3 + 4 + 6 = 24 ;11

:D Yeah thats not it but it works right? If x is a variable rather than the multiplication symble.

[Samuraid]

((14) - 6) * 3 = 24

[Dignified Pauper]

no, each number is used by itself, can't join them. Our group is going awol.

[MecaKane]

You're going to have to wait for <a href="http://www.eyesonff.com/forums/showthread.php?t=59747">>>--heartshot--> ♥</a>to come on, and answer this for you. Anyone else, you couldn't be sure if they're right or not.

[-N-]

If Occam's razor doesn't apply, then why can you only use each number once? Or are you saying that we can use the operators any number of times, but each number no more than once?

edit: By your conditions, doesn't 6 x 4 work? You said we didn't have to use everything.

[Dignified Pauper]

no, i e-mailed my prof, said you have to use them all once. All numbers must be used once. You don't need them all, but you have to use them all.

[Endless]

6/(1-3/4)

[nik0tine]

([1-3]/4) * 6 =24 I think

[crono_logical]

Raf's works :p nik0tine's equals -3 :p

[nik0tine]

Uhh... *looks stupid.

How 'bout this then?
(4/[3-1]) * 6?

Edit: never mind. I think that equals 12. I'll have to do some more thinking.

[tailz]

argh the best i came up with end in 25 or 23 but ill keep trying

[Dignified Pauper]

How is that the answer? I can't get it to work. The negative number in the denominator can't be possible... someone needs to explain this.. hehe


*Nevermind, I read it wrong, thanks for all your help.*

[rubah]

We call this the '24' game.

If someone can solve this one I'd be obliged.

7, 8, 8, 9

(or maybe it's 7, 7, 8, 9 or 7, 8, 9, 9 one of those. those three numbers and one's done twice)
________________________________

We used to play it in fifth grade all the time. Had a contest for it. We'd draw a card that had four numbers on it and would race to solve it. the 7 8 9 one was the only one I don't ever remember being able to solve.

(6, 6, 6, 6 was the easiest, for shizzle.)

[Masamune·1600]

Here's your solution:

7, 8, 8, 9: 9-7=2, then 2*8=16, then 16+8=24

[Max]

gah i hate math