I resent that. I didn't say 1 I said 9.
link
another way to show the solution:
6/2(1+2) = x
you get a '1' if you distribute 2(1+2)
there's no other way to get a 1
6/2(1+2) = 6/(2+4) = 6/6 = 1
6/2(1+2) = 6/(2*3) = 6/6 = 1
but those brackets don't exist when you distribute. They disappear
6/2(1+2) = 6/2*3
6/2 = 3
3*3 = 9
QED
alternatively: 6/2*3 = (3* 6 ) / 2 not 6 / (2*3)
you can only move the multiplication symbol around in an equation, but not the division sign
3*5 = 5*3
3/5 != 5/3
edit again:
I've re-written the exact same question in a way that anybody can solve
http://i51.:bou::bou::bou::bou::bou:...u:/2j3l9uc.jpg