The people who take what we say seriously are always the best part of these threads.
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The people who take what we say seriously are always the best part of these threads.
Oh we were joking?
I for one am dead serious.
Ad hominem. Only a moron would resort to ad hominem.
Too bad for you that Chemical has provided unshakable scientific proof that pop is correct. It's so obvious I have to assume that you agree with us and you're deliberately being dense as some kind of joke. Keep it up then, that's fine. You know it's pop, whether you admit it to yourself or not. The more you deny it, the more you prove it to everyone. Sorry, Comrade. QED.
I'll take both.
Argument from stupidity. It's a logical fallacy most commonly used by "pop" sayers.Quote:
Originally Posted by Dr Unne
What proof? All I see is pseudo-statistics being used for one's own shortcomings as an intellectual. The fact is that soda is a more complete description maintaining the process by which the liquid goes through until its ultimate carbonated form. At best, pop is only the sound the drink makes and thus appeals to those who cannot understand the chemical process, i.e. the lowest common denominator within society.
People who say "pop" are as low as it gets on the intellectual scale.
who wouyld have thought a simple question like which is better coke or pepsi would turn into a debate about soda coke or pop? :p
but just to keep on with the debate i say coke because soda or pop means that id take pepsi if they had it and i wouldnt. :D
coke rules
Yeah, OK, good job. You're a master of the Argument from Being Complete Wrong.
[qq=Yamaneko]What proof? All I see is pseudo-statistics being used for one's own shortcomings as an intellectual. I'm a communist etc. etc.[/qq]
I think the science here may be a bit above your head. Shouldn't you be off with the rest of the proletariat planning a coup?
I have actually taken statistics classes, hillbilly. We learn these things from something called "school." Maybe you should take a visit; you might even learn how to speak English.