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Thread: The Mid-Year Ciddies 2007 - Nominate now!

  1. #106
    One Hundred Chimneys Recognized Member Tavrobel's Avatar
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    Quote Originally Posted by Evastio View Post
    I hope we have different people winning this time and not the same people winning Ciddies repeatedly.
    Impossible! By using the derivation of the "Evastio" formula and the Elitism Postulate as theorized by Maxx Power, owner of all things humble and holy, the Ciddies is one giant popularity contest, based mostly upon people who have been here before 2003, and those in power or recognition. Popular contenders include Rye, Psychotic, BoB, and so on, even if they have done nothing recently. And I do mean nothing. I would not be surprised if Samuraid gets a "Techies" votes, simply because he can plant 600 damage Remote Mines for the low cost of 300 MP, lasting approximately 4 minutes.

    Now, since I have told you, we shall explore how we came to this conclusion.

    By assuming that all polynomials have a value, and that a2 + b2 = c2, one can reduce all sides by a parenthetical value, eventually winding up with the Determinant value, (b2-4ac)/2a. If b is negative, then you have complex, conjugate roots. By substituting the following values for b, determine the function in terms of p and q. The function will look similar to this: 5p(4a2-3q) + radical(21).

    Since p and q have definite values, we may now apply the Elitism Postulate, which states that all Elitists will vote only for other Elitists, sending every real value to a deadlock. However, one in a while, when one vote goes astray, a new Pirate King is elected, and crowned by the anti-Elitist, Maxx Power. a is to be given the imaginary value of -i. (Pie - p) * q should give you an astronomical vlue. However, it can be reduced by using Limit formulae.

    If pp-q = a, then all values for b will be correct, as long as b < 2.00E3 +4. When one brings the equation is graphed, it will look like a negative cubic, starting from the top, with a burp curve. However, hypothetically, if a lovehurts reference is thrown into the mix, it is possible that the answer will come out impossibly different from what is normally gathered, resulting in an Out-of-bounds error, or a Domain of log(x)y. But I'm talking applied math, not theoretical math.

    Therefore, by re-applying the Elitism Postulate with the now reconcilable Christmas formula, and adding the answer to the Evastio formula, you will have the answer of: p/q, with upper bounds of 4, and a lower bound of -5. By re-applying these numbers to the original equation, synthetic divison with a remainder of zero, the answer will come out to be "less than 50% of all Ciddies winners deserve what they have been recognized for." Therefore, it is also possible to assume from this proof and derivation that Lekana will still nominate and vote for me.

    Be proud Maxx! Your efforts and research have finally come to a head!

    Knowledge is power.

  2. #107
    Recognized Member Jessweeee♪'s Avatar
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    o.o

  3. #108
    Some kind of Nature~ Fonzie's Avatar
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    Quote Originally Posted by Tavrobel View Post
    Quote Originally Posted by Evastio View Post
    I hope we have different people winning this time and not the same people winning Ciddies repeatedly.
    Impossible! By using the derivation of the "Evastio" formula and the Elitism Postulate as theorized by Maxx Power, owner of all things humble and holy, the Ciddies is one giant popularity contest, based mostly upon people who have been here before 2003, and those in power or recognition. Popular contenders include Rye, Psychotic, BoB, and so on, even if they have done nothing recently. And I do mean nothing. I would not be surprised if Samuraid gets a "Techies" votes, simply because he can plant 600 damage Remote Mines for the low cost of 300 MP, lasting approximately 4 minutes.

    Now, since I have told you, we shall explore how we came to this conclusion.

    By assuming that all polynomials have a value, and that a2 + b2 = c2, one can reduce all sides by a parenthetical value, eventually winding up with the Determinant value, (b2-4ac)/2a. If b is negative, then you have complex, conjugate roots. By substituting the following values for b, determine the function in terms of p and q. The function will look similar to this: 5p(4a2-3q) + radical(21).

    Since p and q have definite values, we may now apply the Elitism Postulate, which states that all Elitists will vote only for other Elitists, sending every real value to a deadlock. However, one in a while, when one vote goes astray, a new Pirate King is elected, and crowned by the anti-Elitist, Maxx Power. a is to be given the imaginary value of -i. (Pie - p) * q should give you an astronomical vlue. However, it can be reduced by using Limit formulae.

    If pp-q = a, then all values for b will be correct, as long as b < 2.00E3 +4. When one brings the equation is graphed, it will look like a negative cubic, starting from the top, with a burp curve. However, hypothetically, if a lovehurts reference is thrown into the mix, it is possible that the answer will come out impossibly different from what is normally gathered, resulting in an Out-of-bounds error, or a Domain of log(x)y. But I'm talking applied math, not theoretical math.

    Therefore, by re-applying the Elitism Postulate with the now reconcilable Christmas formula, and adding the answer to the Evastio formula, you will have the answer of: p/q, with upper bounds of 4, and a lower bound of -5. By re-applying these numbers to the original equation, synthetic divison with a remainder of zero, the answer will come out to be "less than 50% of all Ciddies winners deserve what they have been recognized for." Therefore, it is also possible to assume from this proof and derivation that Lekana will still nominate and vote for me.

    Be proud Maxx! Your efforts and research have finally come to a head!

    Knowledge is power.
    Don't fill there heads with fairy tales. :twak:

  4. #109
    it's not fun, don't do it Moon Rabbits's Avatar
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    Awesome, something to do on the computer again!

  5. #110
    IF I WERE A BOY~ Dynast-Kid's Avatar
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    Quote Originally Posted by Tavrobel View Post
    Quote Originally Posted by Evastio View Post
    I hope we have different people winning this time and not the same people winning Ciddies repeatedly.
    Impossible! By using the derivation of the "Evastio" formula and the Elitism Postulate as theorized by Maxx Power, owner of all things humble and holy, the Ciddies is one giant popularity contest, based mostly upon people who have been here before 2003, and those in power or recognition. Popular contenders include Rye, Psychotic, BoB, and so on, even if they have done nothing recently. And I do mean nothing. I would not be surprised if Samuraid gets a "Techies" votes, simply because he can plant 600 damage Remote Mines for the low cost of 300 MP, lasting approximately 4 minutes.

    Now, since I have told you, we shall explore how we came to this conclusion.

    By assuming that all polynomials have a value, and that a2 + b2 = c2, one can reduce all sides by a parenthetical value, eventually winding up with the Determinant value, (b2-4ac)/2a. If b is negative, then you have complex, conjugate roots. By substituting the following values for b, determine the function in terms of p and q. The function will look similar to this: 5p(4a2-3q) + radical(21).

    Since p and q have definite values, we may now apply the Elitism Postulate, which states that all Elitists will vote only for other Elitists, sending every real value to a deadlock. However, one in a while, when one vote goes astray, a new Pirate King is elected, and crowned by the anti-Elitist, Maxx Power. a is to be given the imaginary value of -i. (Pie - p) * q should give you an astronomical vlue. However, it can be reduced by using Limit formulae.

    If pp-q = a, then all values for b will be correct, as long as b < 2.00E3 +4. When one brings the equation is graphed, it will look like a negative cubic, starting from the top, with a burp curve. However, hypothetically, if a lovehurts reference is thrown into the mix, it is possible that the answer will come out impossibly different from what is normally gathered, resulting in an Out-of-bounds error, or a Domain of log(x)y. But I'm talking applied math, not theoretical math.

    Therefore, by re-applying the Elitism Postulate with the now reconcilable Christmas formula, and adding the answer to the Evastio formula, you will have the answer of: p/q, with upper bounds of 4, and a lower bound of -5. By re-applying these numbers to the original equation, synthetic divison with a remainder of zero, the answer will come out to be "less than 50% of all Ciddies winners deserve what they have been recognized for." Therefore, it is also possible to assume from this proof and derivation that Lekana will still nominate and vote for me.

    Be proud Maxx! Your efforts and research have finally come to a head!

    Knowledge is power.
    So only oldbies can win?


  6. #111

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    Quote Originally Posted by Tavrobel View Post
    Quote Originally Posted by Evastio View Post
    I hope we have different people winning this time and not the same people winning Ciddies repeatedly.
    Impossible! By using the derivation of the "Evastio" formula and the Elitism Postulate as theorized by Maxx Power, owner of all things humble and holy, the Ciddies is one giant popularity contest, based mostly upon people who have been here before 2003, and those in power or recognition. Popular contenders include Rye, Psychotic, BoB, and so on, even if they have done nothing recently. And I do mean nothing. I would not be surprised if Samuraid gets a "Techies" votes, simply because he can plant 600 damage Remote Mines for the low cost of 300 MP, lasting approximately 4 minutes.

    Now, since I have told you, we shall explore how we came to this conclusion.

    By assuming that all polynomials have a value, and that a2 + b2 = c2, one can reduce all sides by a parenthetical value, eventually winding up with the Determinant value, (b2-4ac)/2a. If b is negative, then you have complex, conjugate roots. By substituting the following values for b, determine the function in terms of p and q. The function will look similar to this: 5p(4a2-3q) + radical(21).

    Since p and q have definite values, we may now apply the Elitism Postulate, which states that all Elitists will vote only for other Elitists, sending every real value to a deadlock. However, one in a while, when one vote goes astray, a new Pirate King is elected, and crowned by the anti-Elitist, Maxx Power. a is to be given the imaginary value of -i. (Pie - p) * q should give you an astronomical vlue. However, it can be reduced by using Limit formulae.

    If pp-q = a, then all values for b will be correct, as long as b < 2.00E3 +4. When one brings the equation is graphed, it will look like a negative cubic, starting from the top, with a burp curve. However, hypothetically, if a lovehurts reference is thrown into the mix, it is possible that the answer will come out impossibly different from what is normally gathered, resulting in an Out-of-bounds error, or a Domain of log(x)y. But I'm talking applied math, not theoretical math.

    Therefore, by re-applying the Elitism Postulate with the now reconcilable Christmas formula, and adding the answer to the Evastio formula, you will have the answer of: p/q, with upper bounds of 4, and a lower bound of -5. By re-applying these numbers to the original equation, synthetic divison with a remainder of zero, the answer will come out to be "less than 50% of all Ciddies winners deserve what they have been recognized for." Therefore, it is also possible to assume from this proof and derivation that Lekana will still nominate and vote for me.

    Be proud Maxx! Your efforts and research have finally come to a head!

    Knowledge is power.
    It came to my head all right. And it made it explode.

    Basically as long as 25% or more people that win Ciddies are people that never got Ciddies before I'm happy.

  7. #112
    What the bliff Recognized Member
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    Quote Originally Posted by Dynast-Kid View Post
    So only oldbies can win?
    No. That would defeat the purpose of the best newbie Ciddie. Unless you consider 1999-2003 new.

  8. #113
    One Hundred Chimneys Recognized Member Tavrobel's Avatar
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    Quote Originally Posted by The Fonz View Post
    Don't fill there heads with fairy tales. :twak:
    Their heads? I will fill it with the truth! But it is the right of the people to decide whether or not to heed me!

    Quote Originally Posted by Dynast-Kid View Post
    So only oldbies can win?
    For the most part, yes.

    Quote Originally Posted by Evastio View Post
    It came to my head all right. And it made it explode.

    Basically as long as 25% or more people that win Ciddies are people that never got Ciddies before I'm happy.
    This is your first step. But it won't happen unless the unknown rise against the elite! The Proletariat will establish an unending freedom, the eternal rule of the people. Let the Party be warned.

  9. #114
    Huh? Flower?! What the hell?! Administrator Psychotic's Avatar
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    More than 50% of the Ciddies last time were won by first-time winners. But hey, let's ignore that! You see, ladies and gentlemen, the reason you didn't win a Ciddie is not because of your own low standard of posting, oh no - it could not possibly be your own fault. It is because of a grand elitist conspiracy to vote for popular members, because if people vote for them in an anonymous competition, perhaps they will allow those folk into their inner circle of internet popularity. Perhaps.

    Watch, you guys. Watch me, evil popular Psychotic. I am going to win TREBLE the amount of Ciddies I won last time. It'll happen. In fact, it already has. 300% of 0 Ciddies = 0 Ciddies = SUX2BEU, UNPOPULAR N00BZ. Sorry guys, it's not my fault I'm a no-talent hack who everybody loves!

  10. #115
    Recognized Member Jessweeee♪'s Avatar
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    More than 50% of the Ciddies last time were won by first-time winners. But hey, let's ignore that! You see, ladies and gentlemen, the reason you didn't win a Ciddie is not because of your own low standard of posting, oh no - it could not possibly be your own fault. It is because of a grand elitist conspiracy to vote for popular members, because if people vote for them in an anonymous competition, perhaps they will allow those folk into their inner circle of internet popularity. Perhaps.
    Christmas would be a fine example of last year's Ciddies. She won practically everything she was nominated for, which was a lot, and she was a newbie I think.

  11. #116
    Chocobocconcini Doomie's Avatar
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    That speech was fantastic. You have my vote!

  12. #117
    Huh? Flower?! What the hell?! Administrator Psychotic's Avatar
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    Loony BoB. 2004, 2005.

    EDIT: loben deleted his post but the one below is a duplicate. That is what I am responding to.

  13. #118

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    Quote Originally Posted by Psychotic View Post
    More than 50% of the Ciddies last time were won by first-time winners. But hey, let's ignore that! You see, ladies and gentlemen, the reason you didn't win a Ciddie is not because of your own low standard of posting, oh no - it could not possibly be your own fault. It is because of a grand elitist conspiracy to vote for popular members, because if people vote for them in an anonymous competition, perhaps they will allow those folk into their inner circle of internet popularity. Perhaps.

    Watch, you guys. Watch me, evil popular Psychotic. I am going to win TREBLE the amount of Ciddies I won last time. It'll happen. In fact, it already has. 300% of 0 Ciddies = 0 Ciddies = SUX2BEU, UNPOPULAR N00BZ. Sorry guys, it's not my fault I'm a no-talent hack who everybody loves!
    name one person that can beet a party you make thats on this forum and I'll believe you.
    July's

  14. #119
    Chocobocconcini Doomie's Avatar
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    Quote Originally Posted by loben View Post

    name one person that can beet a party you make thats on this forum and I'll believe you.
    Look at every Election except the previous one.

  15. #120
    Nerf This~ Laddy's Avatar
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    Haha, I might actualy win something this time!



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