Oh man I hate them.
After playing with my calculator, I have found out that the limit as x->∞ of the arctan(x) is π/2, the arcsec(x) as x->1 = ∞, and little else.
Anything else I should be aware of before trying to do crazy-seeming Improper Integrals problems that look divergent but they actually converge because goshdarn it, wouldn't you just know the arctan(∞) happens to be π/2?

					
						



					
					
					
						
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  it never gets bigger than that.
						
					
				

