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I squared sqrt(x-8)+2. For the purpose of this explanation let sqrt(x-8) equal y.
So here we go.
sqrt(x-8)+2; sqrt(x-8)=y
Substitute.
y+2
Square it.
(y+2)(y+2)=y^2+4y+4
Substitute again.
[sqrt(x-8)]^2+4[sqrt(x-8)]+4
Simplify.
(x-8)+4sqrt(x-8)+4
Simplify more.
x-4+4sqrt(x-8).
Basically, when you square sqrt(x-8)+2, you have to treat it like you would squaring y+2, in other words, you square the y, add the product of 2 times y and 2 times y and square the 2.
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