you can have a fraction in a radical, jesse. you just rewrite it as the square root of the numerator divided by the square root of the denominator, like √(1/2) = √(1)/√(2) then you can multiply top and bottom by √(2) to get rid of the square root in the denominator, but it's completely useless and only jerkfaces make you do that.

for √(1-√(3)/2) you'd multiply the two terms inside the outer √ by two but you'd have to divide by √2 twice on the outside, so:

√((1*2) - 2√(3)/2)) * (1/√(2)) * (1/√(2))

so that simplifies to
√(2 - √(3)) * (1/√(2))<sup>2</sup>

the √ and <sup>2</sup> cancel (square root is basically <sup>1/2</sup> so you multiply them out to get 1) so you just get *(1/2)

[edit- grrrrrrrrrrrrrr gobo!]