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Thread: Algebraic Brain Explosion

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    Gold is the new black Goldenboko's Avatar
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    Default Algebraic Brain Explosion

    So, I've got something I know will be included in a test tomorrow (the test isn't on it, but it's a little detail which will end up hurting me D: ).


    Apparently fractions inside square roots are no-goes. So when you have something that looks like sqrt(1-sqrt(3)/2) you have to get rid of the two. My book ends up showing the answer as 1/2sqrt(2-sqrt(3)) Which confuses me, how did they simplify to get that?

    If it helps here's the original question, "Use the half-angle formulas to determine the exact value of the sin 105 degrees".
    Last edited by Goldenboko; 01-13-2009 at 12:00 AM.

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    Recognized Member Jessweeee♪'s Avatar
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    uhh...so is that one part sqrt<sup>3</sup>/<sub>2</sub> or sqrt3 divided by 2? It's so hard to read radicals this way ;_;

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    Gold is the new black Goldenboko's Avatar
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    Oh whoops.

    sqrt((1-sqrt(3))/2)

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    Old school, like an old fool. Flying Mullet's Avatar
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    See if this helps you write out your formulas:

    1 - (√3)/2
    Figaro Castle

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    Recognized Member Jessweeee♪'s Avatar
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    ...I didn't think you could have a radical in a radical if you couldn't have a fraction in a radical, math is weeeird.

    I got

    (<sup>1</sup>/<sub>2</sub>)√(2-2√(3))



    if that's what you meant to type in the first post then I can help, if not then I'm doing it wrong and will be useless xD

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    Gold is the new black Goldenboko's Avatar
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    Redid the problem, basic math error in the beginning screwed me later on. I'm good

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    Draw the Drapes Recognized Member rubah's Avatar
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    you can have a fraction in a radical, jesse. you just rewrite it as the square root of the numerator divided by the square root of the denominator, like √(1/2) = √(1)/√(2) then you can multiply top and bottom by √(2) to get rid of the square root in the denominator, but it's completely useless and only jerkfaces make you do that.

    for √(1-√(3)/2) you'd multiply the two terms inside the outer √ by two but you'd have to divide by √2 twice on the outside, so:

    √((1*2) - 2√(3)/2)) * (1/√(2)) * (1/√(2))

    so that simplifies to
    √(2 - √(3)) * (1/√(2))<sup>2</sup>

    the √ and <sup>2</sup> cancel (square root is basically <sup>1/2</sup> so you multiply them out to get 1) so you just get *(1/2)

    [edit- grrrrrrrrrrrrrr gobo!]

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    dizzy up the girl Recognized Member Rye's Avatar
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    I'm just squinting at this thread in confusion, trying to remember when I've learned this. I've taken up to Pre-Calc in math, so I must have, but jeez.

    Oh well. I finished all of my math requirements in college, I never have to do any advanced math again! And my Science credit will be down after I take Bio, so I won't even need to solve Chem equations. YAY! &hearts;

    Good luck!


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    I hate chemistry equations. I hate them. My math and my science grades are always totally opposite for the same reason! Math!

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    I'm selling these fine leather jackets Aerith's Knight's Avatar
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    I always think: "Finally a math problem, not some kind of Japanese, post-modern American studies crap." but when I get there everything is already solved. ;_;

    I HATE YOU! jk, just mildly despise


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    Draw the Drapes Recognized Member rubah's Avatar
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    that's because we all think the same thing and hurry to beat each other to be the one to answer.

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    Gold is the new black Goldenboko's Avatar
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    I love asking the question and watching the ensuing dogfight =D

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    We all gotta look smart, you know

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    VICIOUS GEEK SOOT~ヽ(`Д´)ノ scrumpleberry's Avatar
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    Make a maths nerdery thread!

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    Been there, done that.

    Make a physics one instead.


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