As I said:
xD
Also, don't you mean 2 instead of 3, as the zero's of the parabola are 1 and 3.
I just checked in Mathematica, and the
F(x) = Int[ sqrt( x^4 - 8x^3 + 22x^2 - 24x + 9) dx] 0-4
part is still good, but when I looked at the answer for the integral that filled up the entire page... yeah, you really should use Necro's way. xD
If you split them up, the parts just become:
Int [x^2 - 4x + 3 dx]0-1 = 1 1/3
Int [-x^2 + 4x - 3 dx]1-3 = 1 1/3
Int [x^2 -4x + 3 dx]3-4 = 1 1/3
--------------------------------- +
Total = 4
It's good to know both ways though, if you can't find the zero points that easily, like with for example: "x^2 -x -1"