6÷2(1+2)=

[Peegee]

I resent that. I didn't say 1 I said 9.

link

another way to show the solution:

6/2(1+2) = x

you get a '1' if you distribute 2(1+2)

there's no other way to get a 1
6/2(1+2) = 6/(2+4) = 6/6 = 1
6/2(1+2) = 6/(2*3) = 6/6 = 1

but those brackets don't exist when you distribute. They disappear

6/2(1+2) = 6/2*3
6/2 = 3
3*3 = 9
QED

alternatively: 6/2*3 = (3* 6 ) / 2 not 6 / (2*3)

you can only move the multiplication symbol around in an equation, but not the division sign

3*5 = 5*3
3/5 != 5/3

edit again:

I've re-written the exact same question in a way that anybody can solve