force balance at the top of your jump: ∆F=0(not moving), F<sub>jump</sub>+a<sub>g</sub>*-h*m
F=9.81m/(s<sup>2</sup>)*91kg*(-.3m)
F=267.813 kg*m<sup>2</sup>/(s<sup>2</sup>)= 267.8N

267.8 newtons is the force you can exert, so
keeping F the same, and changing a<sub>g</sub> to the gravity on whichever body you're interested in, (say 1.63, for the moon), solve for h
h=1.8m

basically just the earth's gravity divided by the gravity of where you'll be going. Air resistance is more complicated. You could imagine your body as an oval facing into the direction of the jump, then estimate a drag force, and add that to your F, but then you'd have to estimate how fast you're jumping and how relatively dense the atmospheres are on other planets, etc. Too much trouble, really