What's the pressure force of a falling beer can based on certain variables?

[*Laurelindo*]

I felt like trying to calculate how much pressure a beer can would exert on, for example, a glass table, if it was dropped from a certain height, and if it had a certain weight and bottom area.
I figured that I should be able to do it like this:

p = F/A
F = (mv)/t
v = (2gh)^0,5
t = d ÷ v

p = md ÷ At²

...and solving t gives this:

t = (2h ÷ g)^0,5

This gave me the following equation:

p = md ÷ A*(2h/g)

So for example if the beer can had a weight of 1,0 kg and a bottom area of 0,40 dm^<SUBP>2</SUP> then this would mean it had a pressure of 1,228 kPa, or 0,19 psi.
Could this be correct?