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XP / Redhat 7.3 / 98 triple-boot
I want to set up my computer to run Windows XP, RedHat 7.3 and Windows 98. I have two hard drives. One I'm going to use entirely for XP, another I want to use for Linux and 98. Now I already have XP on one HD and Linux on the other, I just want to add 98 to the Linux one, but I don't care if I have to totally reinstall Linux to do it.
What I basically want to know is where to put the partitions. I don't know whether to put the Linux partitions first on the HD or to put the FAT32 one first. I don't know if 98 can find partitions that aren't first on a drive. (I hope it can find the partition at all, really.) I also don't know which order to install the two OS's in. I think 98 clobbers the boot sector when it installs, so I'm probably going to need to fix it if I install 98 second. I was thinking I could partition the drive into a FAT32 and a couple ext3 or whatever, then install 98, then install Linux.
The other thing I'm trying to figure out is how to get XP to boot all the OS's. Currently it boots Linux fine, I had to dump an image of the boot sector (or something) and store it as a file on my XP drive. I don't know how to do it for 98 though.
If there are web sites for this, that'd be nice. It'd probably be too long to explain it all in this post. If someone could give a reall condensed explanation, that'd be good too. *looks for Bleys / crono_logical*
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