Originally posted by PhoenixAsh
I remember someone suggested that maybe recoil is the point of the gunblade, firing the sword down faster.
It all cam about because Squall's apparently doesnt have anywhere for bullets to leave.
If Squall's gunblade has no place for the bullets to leave, it can't generate a recoil! We know this from Neweton's second and third laws of motion...

A small bullet pushing away from the gunblade at high speed would make the much-heavier gunblade move away from the bullet at a much slower speed. This is recoil. However, if there is no place for the bullets to leave, then this cannot happen! And if the blade is supposed to be pushed into the enemy as a result, then any bullet that did come out would be heading in Squall's general direction!

Al Bhed³ - you said that the bullet appears to come out of the top of Seifer's Hyperion... I think you are wrong, and that with the hyperion the bullet passes down the length of the blade (it does appear to be rather thick). The hole at the top is probably just for ejecting empty cases. In fact, I'd like to take a look at the intro again to see if you can see the empty case ejecting when Seifer uses his gunblade against Squall...