Math Forum game Yay!

[radyk05]

a projetile that is fired with an initial velocity v at an angle θ will pass through two points at hight h. show that, if the gun is set for maximun reach, the distance between the two points is

d = v/g * (v^2 - 4*g*h)^(1/2)

where g stands for the gravitational acceleration.
i'm going to make things a bit easier for those who haven't taken a physics or calculus course:
remember that we're dealing in two dimenssions so,
velocity in y, vy = sin θ * v
velocity in x, vx = cos θ * v

the equation for movement are:
x = xinitial + vx,initial * t
y = yinitial + vy,initial + (1/2) * g * t^2

where t stands for time.

that is all that you need.

have fun, i sure did.