Calculus

[Peegee]

I really just need to know if I got the correct answer to the following:

find the limits of the following

1) lim x->∞ sqrt (4x⁸-10x³+x-4)
                &nbs p;       2x⁴-3x

I got '2'

2) lim x->∞ x⁵+8x³-4x+54
                &nbs p;8x⁵+x⁴-3x²-1

I got '1/8'

If you require more info please say so. Thanks!

[-N-]

1 and 1/8

er yeah, AIM convo

explanation for #1:

Ignore all lower order terms. In the numerator, ignore EVERYTHING except the x^8 term, and in the denominator, ignore EVERYTHING except the x^4 term. EVERYTHING else is insignificant. Thus, you have:

sqrt(4x^8)
    2x^4

Which reduces to 1.

You can do this because you're taking an infinity limit. When x gets huge, x^8 is much larger than x^3, and so on. Thus, you only consider the highest-order terms.

[Peegee]

yep -- despite your angry outbursts I did it.

solved it to = 1 :D

ty

[-N-]

Despite my angry outbursts?
I told you like a hundred times to check the square root of 4, man!

[Peegee]

in my defence I had no idea what you were talking about :D

[Doomie]

I'm doing Pre-Cal this year and Calculus last year so this ight help. Does sqrt mean squirt?

[Peegee]

yep

[Mo-Nercy]

You're supposed to be ASIAN! Why the hell would you need help in maths?

[Rye]

You're supposed to be ASIAN! Why the hell would you need help in maths?

Damn, beat to it! PG, you even told me:

"I did calculus today... to see if I'm still azn..."

[Shoeberto]

Okie dokie