He taught those today, after this was due. Something like Gradient of f(x,y) = Lambda gradient g(x,y), right? I didn't really pay attention, because I worked crossword puzzles the whole period.Originally Posted by Endless
I eventually did something here or there, and came up with
X = Y = (Root2C)/3
Z = C/(2root2C)
Several other people came up with the same answer.







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