Originally Posted by Aradae
(1/3)(3) = 3/3 does not equal .9999 because it is a whole. .9999 is a .000001 away from being a whole. 1 is a whole number. .9999 is a decimal. Yes it can be rounded. But it's like when people say there's a 99% chance of a medicine not working, people believe it as fool proof, when one person comes in and the medicine does not work, that is the reason of it not being 100% and or in this case, 1 or a full whole number.
But what number separates .99999~ and 1? The answer is 0.000000~, or 0. Therefore, they are the same number.
(1/3)(3) = 3/3 does not equal .9999 because it is a whole. .9999 is a .000001 away from being a whole. 1 is a whole number. .9999 is a decimal. Yes it can be rounded. But it's like when people say there's a 99% chance of a medicine not working, people believe it as fool proof, when one person comes in and the medicine does not work, that is the reason of it not being 100% and or in this case, 1 or a full whole number.
I always got F's in math and yes I dropped out as well but aradae, please tell me you were kidding cause' I'll laugh with you if you were.
I didn't know you guys already had this argument. Has this board undergone it's chuck norris phase yet
Edit: LOL, CN the texas walker ranger has been filtered to Raol Duke. I'm assuming the mods here grew tired of him too.
Yes. (You're better at articulating your thoughts than I am. :3)
If you add the infinity nothing does, but if there is no infinity and the number spiraled throughout forever, an infinate .00000 with a 1 at the end would as well. .9999999999999999999~ then .00000000000000000>1~. 0 does not = 1.But what number separates .99999~ and 1? The answer is 0.000000~, or 0. Therefore, they are the same number.
(1/3)(3) = 3/3 does not equal .9999 because it is a whole. .9999 is a .000001 away from being a whole. 1 is a whole number. .9999 is a decimal. Yes it can be rounded. But it's like when people say there's a 99% chance of a medicine not working, people believe it as fool proof, when one person comes in and the medicine does not work, that is the reason of it not being 100% and or in this case, 1 or a full whole number.
There's no such thing as an infinite .0000 with a 1 at the end. If something is infinite then it never ends. If there was a 1 at the end then it wouldn't be infinite.If you add the infinity nothing does, but if there is no infinity and the number spiraled throughout forever, an infinate .00000 with a 1 at the end would as well. .9999999999999999999~ then .00000000000000000>1~. 0 does not = 1.But what number separates .99999~ and 1? The answer is 0.000000~, or 0. Therefore, they are the same number.
(1/3)(3) = 3/3 does not equal .9999 because it is a whole. .9999 is a .000001 away from being a whole. 1 is a whole number. .9999 is a decimal. Yes it can be rounded. But it's like when people say there's a 99% chance of a medicine not working, people believe it as fool proof, when one person comes in and the medicine does not work, that is the reason of it not being 100% and or in this case, 1 or a full whole number.
I don't understand anything that I just read.
Then how do we not know there's not something at the end of all the 9's. What if there is a 1 or a 3 or a 4 we can't see due to the fact we think that it's just constant 9's. 1.1 isn't even one. It is 1 and 1/10.There's no such thing as an infinite .0000 with a 1 at the end. If something is infinite then it never ends. If there was a 1 at the end then it wouldn't be infinite.If you add the infinity nothing does, but if there is no infinity and the number spiraled throughout forever, an infinate .00000 with a 1 at the end would as well. .9999999999999999999~ then .00000000000000000>1~. 0 does not = 1.But what number separates .99999~ and 1? The answer is 0.000000~, or 0. Therefore, they are the same number.
(1/3)(3) = 3/3 does not equal .9999 because it is a whole. .9999 is a .000001 away from being a whole. 1 is a whole number. .9999 is a decimal. Yes it can be rounded. But it's like when people say there's a 99% chance of a medicine not working, people believe it as fool proof, when one person comes in and the medicine does not work, that is the reason of it not being 100% and or in this case, 1 or a full whole number.
So if we don't count as 1.1 as 1. (1 1/10)
Why would we count .9999~
DOES DISLIKE ~ = HATE?
The Firefox vs. IE threads are better than this.
Probably.
Sigless
There ISN'T something at the end of all the 9's because there IS no end to all the 9's. .99999~ is an INFINITE amount of decimal places, meaning that the 9s go on forever and ever and ever and ever. 1.1 isn't 1 because 1.1 - 1 = 0.1. 1 - .999999~ = .00000~, which can be written as 0, therefore they are the same number.Then how do we not know there's not something at the end of all the 9's. What if there is a 1 or a 3 or a 4 we can't see due to the fact we think that it's just constant 9's. 1.1 isn't even one. It is 1 and 1/10.There's no such thing as an infinite .0000 with a 1 at the end. If something is infinite then it never ends. If there was a 1 at the end then it wouldn't be infinite.If you add the infinity nothing does, but if there is no infinity and the number spiraled throughout forever, an infinate .00000 with a 1 at the end would as well. .9999999999999999999~ then .00000000000000000>1~. 0 does not = 1.But what number separates .99999~ and 1? The answer is 0.000000~, or 0. Therefore, they are the same number.
(1/3)(3) = 3/3 does not equal .9999 because it is a whole. .9999 is a .000001 away from being a whole. 1 is a whole number. .9999 is a decimal. Yes it can be rounded. But it's like when people say there's a 99% chance of a medicine not working, people believe it as fool proof, when one person comes in and the medicine does not work, that is the reason of it not being 100% and or in this case, 1 or a full whole number.
So if we don't count as 1.1 as 1. (1 1/10)
Why would we count .9999~
IE pwns Firefox IMO
I didn't think you could subtract infinities, yes, it would equal zero with the infinity's but the fact I can't get my head around, is if the 9's stopped for what ever reason, because non-infinitive, 1 - .9999999999999999999999999 would = .0000000000000000000000001There ISN'T something at the end of all the 9's because there IS no end to all the 9's. .99999~ is an INFINITE amount of decimal places, meaning that the 9s go on forever and ever and ever and ever. 1.1 isn't 1 because 1.1 - 1 = 0.1. 1 - .999999~ = .00000~, which can be written as 0, therefore they are the same number.Then how do we not know there's not something at the end of all the 9's. What if there is a 1 or a 3 or a 4 we can't see due to the fact we think that it's just constant 9's. 1.1 isn't even one. It is 1 and 1/10.There's no such thing as an infinite .0000 with a 1 at the end. If something is infinite then it never ends. If there was a 1 at the end then it wouldn't be infinite.If you add the infinity nothing does, but if there is no infinity and the number spiraled throughout forever, an infinate .00000 with a 1 at the end would as well. .9999999999999999999~ then .00000000000000000>1~. 0 does not = 1.But what number separates .99999~ and 1? The answer is 0.000000~, or 0. Therefore, they are the same number.
(1/3)(3) = 3/3 does not equal .9999 because it is a whole. .9999 is a .000001 away from being a whole. 1 is a whole number. .9999 is a decimal. Yes it can be rounded. But it's like when people say there's a 99% chance of a medicine not working, people believe it as fool proof, when one person comes in and the medicine does not work, that is the reason of it not being 100% and or in this case, 1 or a full whole number.
So if we don't count as 1.1 as 1. (1 1/10)
Why would we count .9999~
I just don't see 1 as being an infinite. That's like saying 2.99999999999999~ is 3. and 3.99999999999~ is 4 and so on.
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