Raistlin FUUUUUUUUU

[Bunny]

In which "reality" is a fantasy version of the real world that exists in Shorty's mind.

[NorthernChaosGod]

What if you change but it's behind door number 1 and then everybody laughs at you?

Then you got smurfed by probability and you just take it like a good boy.

I don't understand the issue with these two problems, unless you suck at math.

[rubah]

To add to the 0.99.. thread here:

Please to tell me the value difference of the following numbers:

1
1.0
1.0000
1.000000
1.000000000000000000000000000000
1.000000000000000...

What do you mean they mean the same? BUT THEY ARE DIFFERENT NUMBERS LOSAFLSDJO ASL

I wasn't being facetious in the other thread but I am here.

Different levels of precision. Each additional zero, inherently a significant figure, indicates a greater certainty about the value.

[Peegee]

To add to the 0.99.. thread here:

Please to tell me the value difference of the following numbers:

1
1.0
1.0000
1.000000
1.000000000000000000000000000000
1.000000000000000...

What do you mean they mean the same? BUT THEY ARE DIFFERENT NUMBERS LOSAFLSDJO ASL

I wasn't being facetious in the other thread but I am here.

Different levels of precision. Each additional zero, inherently a significant figure, indicates a greater certainty about the value.

Incorrect - 1 == 1.0000000000....

[Raistlin]

Trailing zeros are significant figures in that they signify a higher level of precision. But that additional precision does not change the value. Also, that precision is not relevant in doing hypothetical calculations, because when you say "1" it clearly implies "1.000...." They would be much more relevant in practice when doing calculations based on measurements.

Really, PG, if you're going to be azn you should be able to counter some trolling attempt from someone who's not only non-azn, but also has female parts. You shame your ethnicity.

[rubah]

very good, westlin! You pulled out the measurements word!

[Peegee]

very good, westlin! You pulled out the measurements word!

make me a sammich you baby making woman

>But that additional precision does not change the value

THAT

>measurement

THAT IS ALSO TRUE

I am not contending that 5.58333583 * 2 = 11. You specified that many decimal places, your answer has that many decimal places.

I'm condending that 1 = 1.00000000 = 1.0000000... and you cannot disagree that the value of the numbers are the same.

derp a herp.

[NeoCracker]

Hippies are superior to the rest of you. We don't need math in our daily lives.

Or soap.

[escobert]

stfu hippies = god

[Clo]

I was worried this thread was about Wesley sex. Thank god.

[Madonna]

I am really concerned when people bring up Welsey's sex life in a discussion about math. My only conclusion can be this: someone is trying to distract us from the math, the math where he is wrong and where .999... and 1 are two disparate numbers.

.999.. is infinitely not 1, but instead infinitely close but never 1. It needs a .000...1 to make it 1, but can never get it. Thus, 1 =/= .999...

[Rantz]

.999... = nonsense^2

Yeah well solve this!!!

[G13]

Speaking of which, we haven't had a "does 0.999... = 1?" thread in a while.

Why in smurf's name did you bring this up? I blame you for all the world's problems.

[Loony BoB]

I prefer the Monty Hall problem if I wanted to blow people's minds.

Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?

Surely the answer is "No, it is not to your advantage"? The chances of the car being behind door one or door two are the same. If you stay with door one, you have a one in two chance of it being a car. If you go to door two, you still have a one in two chance of it being a car. Equal chance? No advantage.

I'm only asking because it seemed really easy to figure out. Waiting for some kind of trick question surprise to show I'm wrong somehow. =|

EDIT: Just read up on it on Wikipedia, very interesting! Never thought about it that way.

[qwertysaur]

I prefer the Monty Hall problem if I wanted to blow people's minds.

Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?

Surely the answer is "No, it is not to your advantage"? The chances of the car being behind door one or door two are the same. If you stay with door one, you have a one in two chance of it being a car. If you go to door two, you still have a one in two chance of it being a car. Equal chance? No advantage.

I'm only asking because it seemed really easy to figure out. Waiting for some kind of trick question surprise to show I'm wrong somehow. =|

EDIT: Just read up on it on Wikipedia, very interesting! Never thought about it that way.

Probability questions are often much more than what they seem. Also it is more advantageous to switch because before a door is opened, each door has a 1/3 probability to have the car, making it a 2/3 chance it does not have the car because it is behind door 2 or 3. Opening an incorrect door does not change the fact that there is a 2/3 chance the car is not behind 2 or 3. You know that there is no car behind 3, so there is a 2/3 chance it is behind door 2.